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Question

At 800 K a reaction mixture contained 0.5 mole of SO2. 0.12 mole of O2 and 5 mole of SO3 at equilibrium. Kc for the equilibrium 2SO2+O22SO3 is 833 lit/ mole. If the voiume of the container is 1 litre, calculate how much O2 is to be added at this equilibrium in order to get 5.2 moles of SO3 at the same temperature.

A
2.34 mole
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B
0.34 mole
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C
1.43 mole
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D
3.23 mole
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Solution

The correct option is B 0.34 mole
Here Kc=[SO3]2[O2][SO2]2=833
volume=1litre
(5.2)2[O2][SO2]2=833
2SO2+O22SO3
neq(1) 0.5 0.12 5
added x
xi 0.5 0.12+x 5
neq 0.50.2 0.12+x0.1 $5.2
from(1)
=(5.2)2(0.02+x)(0.3)2=833
=27.040.09×933=0.02+x
x=27.0474.970.02=0.34mole

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