At 80C, the vapour pressure of pure benzene is 753 mm Hg and of pure toluene 290 mm Hg. Calculate the composition of a liquid in mole percent which at $80$ is in equilibrium with vapour containing 30 mole percent of benzene.

24, 56

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

26 ,54

No worries! We‘ve got your back. Try BYJU‘S free classes today!

56 24

No worries! We‘ve got your back. Try BYJU‘S free classes today!

34 ,76

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 24, 56
Mole % of benzene=30%of solution
Moles of benzene=3080/100=24
Moles of Toluene=7080/100=56
Composition of benzene and Toluene are 24 moles and 56 moles respectively.

Suggest Corrections

Similar questions

Q. At 80C, the vapour pressure of pure benzene is 753 mm Hg and of pure toluene 290 mm Hg. Calculate the composition of a liquid in mole per cent which at 80C is in equilibrium with the vapour containing 30 mole per cent of benzene.

Benzene and toluene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of toluene.

Benzene and toluene form nearly ideal solution .At 313K the vapour pressure of pure benzene is 150mm Hg and of pure toluene is 50 mm Hg .calculate vapour pressure of mixture of these two containing their equal masses at 313 K .

QUESTION 2.38

Benzene and naphthalene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and naphthalene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of naphthalene.

Q. Mole fraction of benzene in the vapours over a solution of benzene and toluene is 0.4. If the original vapour pressure of benzene is

150 m m H g

and toluene is

50 m m H g

, the mole fraction of benzene in the solution is:

Join BYJU'S Learning Program

At 80C, the vapour pressure of pure benzene is 753 mm Hg and of pure toluene 290 mm Hg. Calculate the composition of a liquid in mole percent which at 80 is in equilibrium with vapour containing 30 mole percent of benzene.

The correct option is A 24, 56Mole % of benzene=30%of solutionMoles of benzene=30*80/100=24Moles of Toluene=70*80/100=56Composition of benzene and Toluene are 24 moles and 56 moles respectively.

At 80C, the vapour pressure of pure benzene is 753 mm Hg and of pure toluene 290 mm Hg. Calculate the composition of a liquid in mole percent which at $80$ is in equilibrium with vapour containing 30 mole percent of benzene.

The correct option is A 24, 56
Mole % of benzene=30%of solution
Moles of benzene=3080/100=24
Moles of Toluene=7080/100=56
Composition of benzene and Toluene are 24 moles and 56 moles respectively.