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Question

At 87oC, the following equilibrium is established H2(g)+S(s)H2S(g); KP=7×102
If 0.50 mole of hydrogen and 1.0 mole of sulphur are heated to 87oC in 1.0 L vessel, what will be the partial pressure of H2S at equilibrium?

A
0.966 atm
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B
1.38 atm
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C
0.0327 atm
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D
9.66 atm
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Solution

The correct option is A 0.966 atm
H2(g)+S(s)H2S(g)Concentration at equilibrium0.5x1xx
Kc=[H2S][H2]7×102=x0.5x
x=0.0327
PH2S=(nH2SV)RT0.0327×0.0821×3600.966 atm.

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