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pH the Power of H

At 90 oC, th...

Question

At 90 $^{o}$ C, the $p H$ of $0.001 M$ $K O H$ solution will be:

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Solution

The correct option is C 9
$0.001$ $M$ $K O H$

$\Rightarrow [O H^{-}] = 0.001 M$

$p O H = - l o g_{10} [O H^{-}]$

$p O H = - log (10^{- 3}) = 3$

$p H = p K w - p O H$

But $90^{o} C$ is above room temprature, $p K w$ decreases

$p H < 14 - 3 \Rightarrow p H < 11$

So, $p H = 9$ (Best choice)

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