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pH the Power of H

At 90oC pur...

Question

At $90^{o} C$ pure water has $[H_{2} O^{+}] = 10^{- 6}$ mol $l i t r e^{- 1}$ .The value of $K_{w}$ at $90^{o} C$ is

10^{- 4}

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10^{- 12}

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10^{- 14}

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10^{- 6}

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Solution

The correct option is C $10^{- 12}$
At all temp $[H^{+}] = [O H^{-}]$
$[H^{+}] = 10^{- 6}$
$\Rightarrow [O H^{-}] 10^{- 6}$
$∴ K_{w} = 10^{- 6} \times 10^{- 6} = 10^{- 12}$

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