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Van't Hoff Factor

At 900 k and ...

Question

At 900k and 1atm SO3 is partially dissociated into SO2 and O2 if density of equilibrium mixture is 0.925g÷L what is degree of dissociation . Is 34.12%

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Solution

We Know,

M= DRT/P
M=average mol weight
D= density
T= temperature
P= pressure
M=0.925 x 0.0821 x 900/1= 68.3
Let degree of dissociation be x

Also we have calculated av mol weight,M
68.3= [80(1-x) + 64x + 32(x/2)] / (1+x/2)

Solving this,
x=34.1%

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