At a certain distance from a point charge the electric field is $500 V / m$ and the potential is $3000 V$ . What is this distance:

36 m

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12 m

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6 m

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144 m

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Solution

The correct option is C $6 m$
Given that,

Electric field $E = 500 V / m$

Potential $V = 3000 V$

We know that,

$E = \frac{V}{d}$

$d = \frac{V}{E}$

$d = \frac{3000}{500}$

$d = 6 m$

Hence, the distance is $6 m$

Suggest Corrections

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