At a certain height, a shell at rest explodes into two equal fragments. One of the fragments receives a horizontal velocity $u$ . The time interval after which the velocity vectors will be inclined at $120^{o}$ to each other is:

\frac{u}{\sqrt{3} g}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{\sqrt{3} u}{g}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 u}{\sqrt{3} g}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{u}{2 \sqrt{3} g}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{u}{\sqrt{3} g}$

Since shell explode into two equal part by momentum conservation both fragment will have $u$ velocity in horizontal direction and will further move under force due to .gravity.
Clearly from figure we can see,
$t a n 30_{o} = v_{y} / u$
$u / \sqrt{3} = v_{y}$
From 1st equation of motion,
$v_{y} = u_{y} + g t$ (Assuming downward direction to be positive)
$u / \sqrt{3} g = t$

Suggest Corrections

Similar questions

Q. At high altitudes, a body explodes at rest into two equal fragments with one fragment receiving horizontal velocity of

10 m / s

. Time taken by the two radius vectors connecting point of explosion to fragments to make

90^{\circ}

Q. At high altitude a body at rest explodes into two fragments of equal masses, with one fragment receiving horizontal velocity of

10 m s^{- 1}

. Time taken by the two radius vectors connecting to point of explosion to both the fragments to make

90^{0}

(g = 10 m s^{- 1})

Q. A bomb at rest at the summit of a cliff breaks into two equal fragments. One of the fragments attains a horizontal velocity of

20 \sqrt{3} m / s

. The horizontal distance between the two fragments, when their displacement vectors is inclined at

60^{0}

relative to each other is (g=10\,m/s^2$

Q. A shell of mass 2m fired with a speed u at an angle

θ

to the horizontal explodes at the highest point of its motion into two fragments of mass m each. If one fragment, falls vertically, the distance at which the other fragment falls from the gun is given by

A shell of mass ‘2m’ fired with a speed ‘u’ at angle $^{'} θ^{'}$ to the horizontal explodes at the highest point of its trajectory into two fragments of mass ‘m’ each. If one fragment falls vertically, the distance at which the other fragment falls from the gun is given by

Join BYJU'S Learning Program

At a certain height, a shell at rest explodes into two equal fragments. One of the fragments receives a horizontal velocity u. The time interval after which the velocity vectors will be inclined at 120o to each other is:

At a certain height, a shell at rest explodes into two equal fragments. One of the fragments receives a horizontal velocity $u$ . The time interval after which the velocity vectors will be inclined at $120^{o}$ to each other is: