Question

At a certain location, the strength of the electric field is $30.0N/C$. A charge of $3.00C$ is placed at this location.
How much force does this charge experience due to the electric field?

• A. $90.0N$
• B. $10.0N$
• C. $0.100N$
• D. $270N/C$
• E. $3.33N/C$

Answer 1

Answer: (A)

$90.0N$

Given : $q=3.00$ C

Strength of electric field $E=30.0$ $N/C$

Thus force experienced $F=qE=3.00\times 30.0=90.0$ $N$