Question

At a certain locations, the strength of the electric field is 30.0 N/C. A charge of 3.00 C is placed at this location.
How much force does this charge experience due to the electric field?

• A. 90.0 N
• B. 10.0 N
• C. 0.100 N
• D. 270 N/C
• E. 3.33 N/C

Answer 1

The correct option is A 90.0 N

Given : Test charge $q=3.00$ C

Strength of electric field at a point $E=30.0$ N/C

Thus force experienced by test charge $F=qE=3.00\times 30.0=90.0$ N