Question

At a certain place, the angle of dip is ${30}^{\circ }$ and the horizontal component of earth’s magnetic field is 0.50 oersted. The earth’s total magnetic field is $\frac{1}{\sqrt{x}}$ oersted. Find x.

Answer 1

$\text{Earth's total magnetic field}$


$B_H$ = horizontal component of earth's field
B = earths total magnetic field
$\varphi$ = angle of dip

$B_H=B\cos \varphi$

$B=\frac{B_H}{\cos \varphi }=\frac{0.5}{\cos {30}^{\circ }}=\frac{\left(0.5\right)\left(2\right)}{\sqrt{3}}=\frac{1}{\sqrt{3}}$

comparing with $\frac{1}{\sqrt{x}}$
x = 3