At a certain place, the horizontal component $B_{0}$ and the vertical component $V_{0}$ of the earth's magnitude are equal. The total intensity at that place will be

\sqrt{2 B_{0}}

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3 \sqrt{2 B_{0}}

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4 \sqrt{2 B_{0}}

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5 \sqrt{2 B_{0}}

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Solution

The correct option is B $\sqrt{2 B_{0}}$
$B_{0} = V_{0}$
also total intensity $B = \sqrt{B_{0}^{2} + V_{0}^{2}} B = \sqrt{2} B_{0}$

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