Question

At a certain place the horizontal component of earth's magnetic field is $\sqrt{3}$ times the vertical component. The angle of dip at that place is

• A. ${60}^{\circ }$
• B. ${30}^{\circ }$
• C. ${45}^{\circ }$
• D. ${37}^{\circ }$

Answer 1

The correct option is B ${30}^{\circ }$

$tan\delta =\frac{B_V}{B_H}$
where $\delta$ is angle of dip, $B_V\text{and}{B}_H$ are vertical and horizontal components of Earth’s Magnetic Field.
$tan\delta =\frac{B_V}{\sqrt{3}{B}_V}\Rightarrow \delta ={30}^{\circ }$