Question

At a certain place, the horizontal component of earth's magnetic field is $\sqrt{3}$ times the vertical component. The angle of dip at that place is

• A. ${60}^{\circ }$
• B. ${45}^{\circ }$
• C. ${90}^{\circ }$
• D. ${30}^{\circ }$

Answer 1

The correct option is D ${30}^{\circ }$

$B_H=\sqrt{3}{B}_V$, also $tan\theta =\frac{B_V}{B_H}=\frac{1}{\sqrt{3}}\Rightarrow \theta ={30}^{\circ }$