Question

At a certain place, the horizontal component of earth’s magnetic field is $\sqrt{3}$ times the vertical component. The angle of dip (in degrees) at that place is

Answer 1

$\text{Angle of dip}$



$B_H$ = horizontal component of earth’s field
$B_V$ = vertical component earth’s field
$\varphi$ = angle of dip
is given that $B_H=\sqrt{3}{B}_V$
then,

$tan\varphi =\frac{B_V}{B_H}=\frac{1}{\sqrt{3}}=\tan {30}^{\circ }$

$\varphi ={30}^{\circ }$