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Standard XII

Physics

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At a certain ...

Question

At a certain temperature for which $R T = 25 l i t . a t m . m o l^{- 1}$ , the density of a gas, in gm $l i t^{- 1}$ , is $d = 2.00 P + 0.020 P^{2}$ , where P is the pressure in atmosphere. The molecular weight of the gas in gm $m o l^{- 1}$ is:

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Solution

The correct option is C 50
The relationship between the molecular weight and density is $L t P \to 0 \frac{d}{p} = \frac{M}{R T}$ .
Substitute values in the above expression.
$M = 2 R T = 50$ .
Thus the molecular weight is $50 g m m o l^{- 1}$ .

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At a certain temperature for which RT=25lit.atm.mol−1, the density of a gas, in gm lit−1, is d=2.00P+0.020P2, where P is the pressure in atmosphere. The molecular weight of the gas in gm mol−1 is:

The correct option is C 50The relationship between the molecular weight and density is LtP→0dp=MRT. Substitute values in the above expression.M=2RT=50.Thus the molecular weight is 50gmmol−1.

At a certain temperature for which $R T = 25 l i t . a t m . m o l^{- 1}$ , the density of a gas, in gm $l i t^{- 1}$ , is $d = 2.00 P + 0.020 P^{2}$ , where P is the pressure in atmosphere. The molecular weight of the gas in gm $m o l^{- 1}$ is:

The correct option is C 50
The relationship between the molecular weight and density is $L t P \to 0 \frac{d}{p} = \frac{M}{R T}$ .
Substitute values in the above expression.
$M = 2 R T = 50$ .
Thus the molecular weight is $50 g m m o l^{- 1}$ .