At a certain temperature, the vapour pressure of water is 90 mm. At the same temperature the vapour pressure of a solution containing a non-volatile solute is 81 mm. The relative lowering of vapour pressure is :

9

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0.9

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10

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0.1

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Solution

The correct option is D $0.1$
The relative lowering in vapour pressure $= \frac{p^{0} - p}{p^{0}}$
$p^{0}$ is the vapour pressure of pure solvent and p is the vapour pressure of the solution.

Given that,
$p^{0} = 90 m m$
$p = 81 m m$
The relative lowering in vapour pressure $= \frac{p^{0} - p}{p^{0}} = \frac{90 - 81}{90} = 0.1$

Option D is correct.

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At a certain temperature, the vapour pressure of water is 90 mm. At the same temperature the vapour pressure of a solution containing a non-volatile solute is 81 mm. The relative lowering of vapour pressure is :

The correct option is D 0.1The relative lowering in vapour pressure =p0−pp0p0 is the vapour pressure of pure solvent and p is the vapour pressure of the solution.Given that,p0=90 mmp=81 mm The relative lowering in vapour pressure =p0−pp0=90−8190=0.1Option D is correct.