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Question

At a certain time, a radioactive sample contains 2×1020 atoms and its disintegration rate is 3×1010 atoms/sec. When 2×1015 atoms are left to decay, its disintegration rate will be (atoms/sec)

A
1×105
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B
2×105
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C
3×105
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D
4×105
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Solution

The correct option is C 3×105
We know that,

Disintegration rate=R=dNdt=λN

RN

R1R2=N1N2

3×1010R2=2×10202×1015

R2=3×105 atoms/sec

Hence, (C) is the correct answer.

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