At a certain time in a deer park, the number of heads and number of legs of deer and human visitors was counted and it was found that there were $39$ heads and $132$ legs. find the number of deers and human visitors in the park. (Solve graphically)

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Solution

Let x be the total no of legs of deer
let y be the total no of legs of visitors.
∴x + y = 132
∵1deer has 4 legs and 1 head & 1 visitor has 2 legs and 1 head
∴x/4 + y/2 = 39
plotting the graph we get the point of intersection which is the value of x and y.
thus from the graph we can say x = 108 and y=24
∴ num of deers = 108/4 = 27
∴ num of visitors = 24/2 = 12

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At a certain time in a deer park, the number of heads and number of legs of deer and human visitors was counted and it was found that there were 39 heads and 132 legs. find the number of deers and human visitors in the park. (Solve graphically)

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