Question

At a certain time in a zoo, the number of heads and the number of legs of tiger and peacocks were counted and it was found that there were $47$ heads and $152$ legs. Find the number of tigers and peacocks in the zoo.

• A. $\text{No. of tigers}=27,\text{No. of peacocks}=29$
• B. $\text{No. of tigers}=22,\text{No. of peacocks}=20$
• C. $\text{No. of tigers}=29,\text{No. of peacocks}=18$
• D. $\text{No. of tigers}=27,\text{No. of peacocks}=20$

Answer 1

The correct option is C $\text{No. of tigers}=29,\text{No. of peacocks}=18$

Let $x$ be the number of tigers and $y$ be the number of peacocoks.
According to conditions given,
$x+y=47$...(i)
$4x+2y=152$ ....(ii)

On solving the above equations, we get
$x=29$ and $y=18$
Hence, number of tigers = $29$ and number of peacocks $=18$