Question

At a certain time of the day, a man 6 feet tall, casts his shadow 8 feet long. Find the length of the shadow cast by a building 45 feet high, at the same time which is next to the man.

Answer 1

Let the length of the shadow of the building $=x$.
In $△$ABC, AB || DE (both are standing vertically on the ground)
$\frac{AB}{DE}=\frac{BC}{EC}$
$\frac{45}{6}=\frac{x}{8}\Rightarrow x=\frac{45\times 8}{6}=60ft$
$\therefore$ Length of shadow cast by the building is $60ft$.