Question

At a certain volume of methane diffuses in 10 seconds through a porous partition. The time taken by an equal volume $O_2$ to diffuse under similar condition is?

• A. 7.07 sec
• B. 5 sec
• C. 14.14 sec
• D. 20 sec

Answer 1

The correct option is A 7.07 sec

$\text{Time required for diffusion}\propto \frac{1}{\sqrt{\text{Molecular wt.}}}$

$\therefore \frac{t_{O_2}}{t_{C{H}_3}}=\sqrt{\frac{M_{C{H}_3}}{M_{O_2}}}$

$\therefore t_{O_2}=t_{C{H}_4}\sqrt{\frac{M_{C{H}_4}}{M_{O_2}}}=10\sqrt{\frac{16}{32}}=7.07sec$