CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

At a conference, every member attending the event makes a handshake with every other member. If there were 105 handshakes in all, what was the number of members attending the conference?


A

15

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

14

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

13

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

16

No worries! We‘ve got your back. Try BYJU‘S free classes today!
E

20

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

15


Let there be x member attending the conference.
So,
x(x1)212=105
x2x=210
x2x210=0
x215x+14x210=0
x(x15)+14(x15)=0
(x15)(x+14)=0
x=15, 14 But -ve sign is ignored
So,
x=15


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorising Denominator
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon