At a constant pressure of $200, 000$ Pa a gas expands from a volume of $1.0 c u b i c$ meter to $2.0$ cubic meters.
If the gas absorbs $100, 000 J$ of energy during this expansion, what is the change in internal energy of the gas during the expansion?

500, 000 J

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300, 000 J

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- 500, 000 J

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- 300, 000 J

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- 100, 000 J

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Solution

The correct option is E $- 100, 000 J$
Given : $Q = + 100, 000$ $J$
Change in volume $Δ V = 2.0 - 1.0 = 1.0$ $m^{3}$
Work done by the gas $W = P Δ V = 200, 000 \times 1.0 = 200, 000$ $J$
From 1st law, $Q = Δ U + W$
$∴$ $100, 000 = Δ U + 200, 000$ $⟹ Δ U = - 100, 000$ $J$

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At a constant pressure of 200,000 Pa a gas expands from a volume of 1.0 cubic meter to 2.0 cubic meters.If the gas absorbs 100,000 J of energy during this expansion, what is the change in internal energy of the gas during the expansion?

The correct option is E −100,000 JGiven : Q=+100,000 JChange in volume ΔV=2.0−1.0=1.0 m3Work done by the gas W=PΔV=200,000×1.0=200,000 JFrom 1st law, Q=ΔU+W∴ 100,000=ΔU+200,000 ⟹ΔU=−100,000 J

At a constant pressure of $200, 000$ Pa a gas expands from a volume of $1.0 c u b i c$ meter to $2.0$ cubic meters.
If the gas absorbs $100, 000 J$ of energy during this expansion, what is the change in internal energy of the gas during the expansion?

The correct option is E $- 100, 000 J$
Given : $Q = + 100, 000$ $J$
Change in volume $Δ V = 2.0 - 1.0 = 1.0$ $m^{3}$
Work done by the gas $W = P Δ V = 200, 000 \times 1.0 = 200, 000$ $J$
From 1st law, $Q = Δ U + W$
$∴$ $100, 000 = Δ U + 200, 000$ $⟹ Δ U = - 100, 000$ $J$