At a constant temperature, a gas at a pressure of 750 mm of mercury occupies a volume of 1000 ${cm}^{3}$ . If volume is decreased by 40%, find the new pressure.

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Solution

$P_{1} = 750 mm Hg P_{2} = ? V_{1} = 1000 {cm}^{3} The 40 % of initial volume = \frac{40}{100} \times 1000 = 400 {cm}^{3} V_{2} = 1000 - 400 = 600 {cm}^{3} P_{1} V_{1} = P_{2} V_{2} 750 \times 1000 = P_{2} \times 600 P_{2} = \frac{750 x 1000}{600} = 1250 mm Hg$

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