Question

At a constant temperature a gas is initially at 2 atm pressure. To compress it to $(\frac{1}{8}{)}^{th}$ of its initial volume, pressure to be applied is

• A. 4 atm
• B. 8 atm
• C. 12 atm
• D. 16 atm

Answer 1

The correct option is D

16 atm

$P_1{V}_1=P_2{V}_2$
$P_1=2atm,V_1=Vml$
$P_2=?,V_2=\frac{V}{8}ml$
$2\times V=P_2\times \frac{V}{8}$
$P_2=16atm$