At a constant temperature a gas is initially at 2 atm pressure. To compress it to ${(\frac{1}{8})}^{t h}$ of its initial volume, pressure to be applied is ___

4 atm

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8 atm

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12 atm

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16 atm

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Solution

The correct option is D
16 atm

When the temperature of a gas is kept constant, the volume of a fixed mass of gas is inversely proportional to its pressure i.e. PV = constant or $P_{1} V_{1} = P_{2} V_{2}$
$P_{1} = 2 a t m, V_{1} = V m l$
$P_{2} = ?, V_{2} = \frac{V}{8} m l$
$2 \times V = P_{2} \times \frac{V}{8}$
$P_{2} = 16 a t m$

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At a constant temperature a gas is initially at 2 atm pressure. To compress it to(18)th of its initial volume, pressure to be applied is ___

The correct option is D 16 atm When the temperature of a gas is kept constant, the volume of a fixed mass of gas is inversely proportional to its pressure i.e. PV = constant or P1V1=P2V2 P1=2 atm, V1=Vml P2=?, V2=V8ml 2×V=P2×V8 P2=16 atm

At a constant temperature a gas is initially at 2 atm pressure. To compress it to ${(\frac{1}{8})}^{t h}$ of its initial volume, pressure to be applied is ___