At a depth of 1000 m in an ocean, what is the absolute pressure? Given density of sea water is $1.03 \times 10^{3} k g m^{- 3}, g = 10 m s^{- 2}$

104 atm

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100 atm

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108 atm

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110 atm

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Solution

The correct option is A 104 atm
Given: $h = 1000 m, d = 1.03 \times 10^{3} k g / m^{3}, g = 10 m / s^{2}$
The absolute pressure is given by: absolute pressure = pressure of water + atmospheric pressure
$P = h d g + 1 a t m = 1000 \times 1.03 \times 10^{3} \times 10 + 1 a t m = 1.03 \times 10^{7} P a + 1 a t m$
$P = 103 a t m + 1 a t m = 104 a t m$

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