Question

At a depth of 1000 m in the ocean ,what is the gauge pressure when density of sea water is given $1.03\times {10}^3$ $kg{m}^{-3}$? Take $g=10m{s}^{-2}.$

• A. 675 atm
• B. 103 atm
• C. 203 atm
• D. 244 atm

Answer 1

The correct option is B 103 atm

Given : $h=1000$ m, $\rho =1030$ $kg/m^3$

Gauge pressure at a depth $h$, $P_g=\frac{\rho gh}{{10}^5}$ atm

$\therefore$ $P_g=\frac{1030\times 10\times 1000}{{10}^5}=103$ atm