Question

At a given place, a mercury barometer records a pressure of $0.70m$ of Hg. What would be the height of water column if mercury in barometer is replaced by water? Take R.D. of mercury $=13.6$

• A. $9.52m$
• B. $19.04m$
• C. $5.76m$
• D. $9m$

Answer 1

The correct option is A $9.52m$

Relative density $=\frac{\text{height of water}}{\text{height of mercury}}$
$\Rightarrow 13.6=\frac{\text{height of water}}{0.70}$
$\text{height of water}=13.6\times 0.70=9.52m$