At a given temperature and pressure 64 gm of Oxygen and X gm of H $_{2}$ occupy the same volume. Then x= ......gm

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Solution

The correct option is D 4
Since they occupy same volume, the two gases should contain same number of molecules, i.e. they have same number of moles.
Now 1 mole of oxygen = 32gm.
Hence 64 gm = 2 mole of oxygen.
$∴$ number of moles of hydrogen is 2.
1 mole of hydrogen= 2gm
Hence X= 4gm

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At a given temperature and pressure 64 gm of Oxygen and X gm of H2 occupy the same volume. Then x= ......gm

The correct option is D 4Since they occupy same volume, the two gases should contain same number of molecules, i.e. they have same number of moles.Now 1 mole of oxygen = 32gm.Hence 64 gm = 2 mole of oxygen.∴ number of moles of hydrogen is 2.1 mole of hydrogen= 2gmHence X= 4gm

At a given temperature and pressure 64 gm of Oxygen and X gm of H $_{2}$ occupy the same volume. Then x= ......gm

The correct option is D 4
Since they occupy same volume, the two gases should contain same number of molecules, i.e. they have same number of moles.
Now 1 mole of oxygen = 32gm.
Hence 64 gm = 2 mole of oxygen.
$∴$ number of moles of hydrogen is 2.
1 mole of hydrogen= 2gm
Hence X= 4gm