Question

At a given temperature equilibrium is attained when 50% of each reactant is convert into the products.
$A\left(g\right)+B\left(g\right)\rightleftharpoons C\left(g\right)+D\left(g\right)$
If amount (in mol) of $B\left(g\right)$ is doubled percentage of $B$ convert into products will be:

• A. $100$
• B. $50$
• C. $66.67$
• D. $33.33$

Answer 1

The correct option is D $33.33$

In the given equation equilibrium attained. When, $A,B,C,D$ are equal. $\therefore$ $K=1$

At starting $A=x$, $B=2x$, $C=0$, $D=0$

Some time. $A=x-y$, $B=2x-y$, $C=y$, $D=y$

$k=\frac{\left[y\right]\left[y\right]}{[x-y][2x-y]}[k=1]$

$y^2=[x-y][2x-y]\Rightarrow y^2={2x}^2-3xy+y^2$

$\Rightarrow \frac{y}{x}=\frac{2}{3}=\frac{2}{3}\times$ initial $\left[B\right]$

$\therefore$ % of $B$ convert in to product is $33.33$%.