At a given temperature, total vapour pressure (in torr) of a mixture of volatile components A and B is given by $P_{T o t a l} = 120 - 75 X_{B}$ hence, the vapour pressure of pure A and B respectively (in Torr) are:

120, 75

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120, 195

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120, 45

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75, 45

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Solution

The correct option is C $120, 45$
$P_{T o t a l} = 120 - 75 X_{B} = P_{A}^{o} X_{A} + P_{B}^{o} X_{B}$

But $X_{A} = 1 - X_{B}$

Hence, $P_{T o t a l} = 120 - 75 X_{B} = P_{A}^{o} (1 - X_{B}) + P_{B}^{o} X_{B} = P_{A}^{o} - (P_{A}^{o} - P_{B}^{o}) X_{B}$

Hence, $P_{A}^{o} = 120$ and $P_{B}^{o} = 120 - 75 = 45$

Hence, the correct option is $C$

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Similar questions

Q. At a given temperature, total vapour pressure in Torr of a mixture volatile components A and B is given by

P_{T o t a l} = 120 - 75 X_{B}

Hence, vapour pressure of pure A and B respectively (in Torr) are ?

At a given temperature, the total vapour pressure (in Torr) of a mixture of volatile components A and B is given by P = 120 - 75 XBhence vapour pressure of pure A and B respectively (in Torr) are -

Q. At a given temperature, total vapour pressure in Torr of a mixture of volatile components A and B is given by

P_{T o t a l}

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hence, vapour pressure of pure A and B
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Q. At a given temperature, total vapour pressure in Torr of a mixture of volatile components A and B is given by

P_{T o t a l}

120 + 75 X_{B}

hence, vapour pressure of pure A and B
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At a given temperature, total vapour pressure (in torr) of a mixture of volatile components A and B is given by PTotal=120−75XB hence, the vapour pressure of pure A and B respectively (in Torr) are:

The correct option is C 120,45PTotal=120−75XB=PoAXA+PoBXBBut XA=1−XBHence, PTotal=120−75XB=PoA(1−XB)+PoBXB=PoA−(PoA−PoB)XBHence, PoA=120 and PoB=120−75=45Hence, the correct option is C

At a given temperature, total vapour pressure (in torr) of a mixture of volatile components A and B is given by $P_{T o t a l} = 120 - 75 X_{B}$ hence, the vapour pressure of pure A and B respectively (in Torr) are: