At a particular instant velocity and acceleration of a particle are (−^i+^j+2^k)m/s and (3^i−^j+^k)m/s respectively at the given instant particle's speed is:
A
increasing
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B
decreasing
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C
constant
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D
can't be say
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Solution
The correct option is A increasing We can say by calculating the angle between them. If it is between 0 and 90, we can say that the velocity is increasing because some component of acceleration increases the velocity, or else it will be decreasing.
cosA=(a1a2+b1b2+c1c2)thesumofmagnitudeofvectors
cosA=4(2√11)
cosA=2√11
Thus A lie between 0 and 90 and thus its velocity is increasing.