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Hardy-Weinberg Principle

At a particul...

Question

At a particular locus, frequency of “A” allele is 0.6 and that of “a” is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?

A

0.36

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B

0.16

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C

0.24

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D

0.48

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Solution

The correct option is D 0.48
As per Hardy-Weinberg equation
$p^{2} + 2 p q + q^{2} = 1$
Given,
p = 0.6
q = 0.4
Heterozygotes frequency = 2 pq
$2 q p = 2 \times 0.6 \times 0.4 = 0.48$

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