Question

At a particular locus, frequency of ‘A’ allele is 0.6 & that of ‘a’ is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?

• A. 0.3
• B. 0.16
• C. 0.24
• D. 0.48

Answer 1

The correct option is D 0.48

Frequency of heterozygotes = 2pq

Here, p = 0.6, q = 0.4.

$\therefore$ Frequency of heterozygotes $=2\times 0.6\times 0.4=0.48$