At a particular point in the channel, the specific energy and velocity of flow are given by 1.5 m- kg/kg and 2.5m/s respectively. What is the depth of flow in the channel at the point?
A
0.5
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B
2.32
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C
1.18
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D
2.5
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Solution
The correct option is C 1.18 ∴E=y+v22g 1.5=y+(2.5)2(2×9.81) ∵y=1.18m Hence, the depth of flow (y)=1.18m.