At a particular temperature, the equilibrium concentrations of the substances in the previous question are as follows: [NO2Cl] = 0.5 M, [Cl2] = 0.3 M, [NO2] = 0.2 M. What is the value of the equilibrium constant for this reaction?
A
2.1
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B
0.48
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C
0.0357
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D
20.83
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E
208.83
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Solution
The correct option is C 20.83 The reaction is 2NO2Cl→2NO2+Cl2 The equilibrium constant K=[NO2Cl]2[NO2]2[Cl2] K=(0.5)2(0.2)2×0.3=20.83