MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Characteristics of Equilibrium Constant

At a particul...

Question

At a particular temperature, the equilibrium constant for
$2 {N O}_{2} (g) ⇌ N_{2} O_{4} (g)$ is one. The same reaction is carried out in a container of volume just half of the former. Will the value of $[N_{2} O_{4}] / {[{N O}_{2}]}^{2}$ be equal to $1$ if no reaction occurred? Will the equilibrium constant change by this change in volume?

Open in App

Solution

${2 N O}_{2} ⇌ N_{2} O_{4} K = 1$
If we half the volume of container partial pressure or concentration of species double.
Hence $\frac{[N_{2} O_{4}]}{{[{N O}_{2}]}^{2}}$ value will be $1 / 2$ not equal to $1$
$K$ of reaction doesn't depend on volume changes.
Hence $K = 1$
$K$ only changes with the temperature.

Suggest Corrections

thumbs-up

0

Similar questions

Q. Consider the following equilibrium in a closed container:

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

At a fixed temperature, the volume of the reaction container is halved. For this change, which of the given statements holds true regarding the equilibrium constant

(K_{p})

and degree of dissociation

(α)

Q. Consider the following equilibrium in a closed container

N_{2} O_{4} (g) ⇌ 2 {N O}_{2} (g)

At a fixed temperature, the volume of the reaction container is halved. For this change, which of the following statement holds true regarding the equilibrium constant

(K_{p})

and degree of dissociation

(α)

?

Q. For the reaction in equilibrium,

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

The concentrations of

N_{2} O_{4}

N O_{2}

at equilibrium are

4.8 \times 10^{- 2}

1.2 \times 10^{- 2} m o l L^{- 1}

respectively. The value of

K_{c}

for this reaction is:

Q. The decomposition of

N_{2} O_{4}

{N O}_{2}

280 K

in chloroform. When equilirbrium has been established,

0.2

N_{2} O_{4}

2 \times 10^{- 3}

{N O}_{2}

2

litre solution. The equilibrium constant for the reaction,

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

Q. The equilibrium constant

K_{p}

for the reaction

N_{2} O_{4} (g) ⇌ {2 N O}_{2} (g)

4.5

. What would be the average molar mass (in g/mol) of an equilibrium mixture of

N_{2} O_{4}

{N O}_{2}

formed by the dissociation of pure

N_{2} O_{4}

at a total pressure of

2

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Equilibrium Constants

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Characteristics of Equilibrium Constant

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon