At a particular temperature, the ratio of molar conductance to specific conductance of 0.01 M NaCl solution is:

10^{5} c m^{3} m o l^{- 1}

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10^{3} c m^{3} m o l^{- 1}

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10 c m^{3} m o l^{- 1}

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10^{5} c m^{2} m o l^{- 1}

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Solution

The correct option is A $10^{5} c m^{3} m o l^{- 1}$
$∵ Λ_{m} = \frac{κ \times 1000}{C (Molarity)}$
$\frac{Λ_{m}}{κ} = \frac{1000}{0.01}$ [Given, molarity of NaCl = 0.01 M]
$∴ \frac{Λ_{m}}{κ} = 10^{5} c m^{3} m o l^{- 1}$

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At a particular temperature, the ratio of molar conductance to specific conductance of 0.01 M NaCl solution is:

The correct option is A 105 cm3mol−1∵ Λm=κ×1000C(Molarity) Λmκ=10000.01 [Given, molarity of NaCl = 0.01 M] ∴ Λmκ=105cm3mol−1

The correct option is A $10^{5} c m^{3} m o l^{- 1}$
$∵ Λ_{m} = \frac{κ \times 1000}{C (Molarity)}$
$\frac{Λ_{m}}{κ} = \frac{1000}{0.01}$ [Given, molarity of NaCl = 0.01 M]
$∴ \frac{Λ_{m}}{κ} = 10^{5} c m^{3} m o l^{- 1}$