Question

At a place of Earth, the vertical component of Earth's magnetic field is $\sqrt{3}$ times its horizontal component. The angle of dip at this place is _____.

• A. ${60}^{\circ }$
• B. ${30}^{\circ }$
• C. ${45}^{\circ }$
• D. $0^{\circ }$

Answer 1

Answer: (A)

${60}^{\circ }$

As, vertical component of Earth's magnetic field,
$B_V=\sqrt{3}{B}_H$
Angle of dip at any place is given by
$\tan \delta =\frac{B_V}{B_H}=\frac{\sqrt{3}{B}_H}{B_H}=\sqrt{3}$
$\Rightarrow \delta ={\tan }^{-1}\left(\sqrt{3}\right)={60}^{\circ }$.