Question

At a place on Earth, the vertical component of Earth's magnetic field is $\sqrt{3}$ times its horizontal component. The angle of dip at this place is ___________

• A. ${30}^o$
• B. ${60}^o$
• C. ${45}^o$
• D. $0^o$

Answer 1

The correct option is B ${60}^o$

Relation between Earth's horizontal $B_H$ and vertical component $B_V$ of magnetic field is given by
$B_V=B_H\tan \delta$
where $\delta$ is the angle of dip.
Given : $B_V=\sqrt{3}{B}_H$
$\therefore$ $\sqrt{3}{B}_H=B_H\tan \delta$
$⟹\tan \delta =\sqrt{3}$
$⟹\delta ={60}^o$
So, option B is correct.