Question

At a place, the angle of dip is 30${}^0$. If the horizontal component of earth's field is $B_H$, then the net field intensity at the place will be :

• A. $\frac{B_H}{2}$
• B. $\frac{2B_H}{\sqrt{3}}$
• C. $B_H\sqrt{2}$
• D. $B_H\sqrt{3}$

Answer 1

The correct option is B $\frac{2B_H}{\sqrt{3}}$

The Horizontal component of magnetic field intensity is given by,
$I\cos \theta =H$
(from the data given from question)
$I\frac{\sqrt{3}}{2}=B_H$
$I=\frac{2B_H}{\sqrt{3}}$