At a point in a structure- there are two mutually perpendicular tensile stresses of 800 kg-cm2 and 400 kg-cm2- If the Poisson-s ratio -0-25- what would be the equivalent stress in simple tension according to maximum principal strain theory-

According to maximum principal strain theory nbsp; nbsp; nbsp;fE=(σ_1 μσ_2)E The equivalent tensile stress nbsp; nbsp; nbsp;f=800 0.25× 400 ...

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Strength of Materials

Maximum Principal Strain Theory

At a point in...

Question

At a point in a structure, there are two mutually perpendicular tensile stresses of 800 $k g / c m^{2}$ and 400 $k g / c m^{2}$ . If the Poisson's ratio $μ = 0.25,$ what would be the equivalent stress in simple tension according to maximum principal strain theory?

1200

k g / c m^{2}

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900

k g / c m^{2}

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700

k g / c m^{2}

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400

k g / c m^{2}

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Solution

The correct option is C 700 $k g / c m^{2}$
According to maximum principal strain theory
$\frac{f}{E} = \frac{(σ_{1} - μ σ_{2})}{E}$
The equivalent tensile stress
$f = 800 - 0.25 \times 400$

$= 700 k g / c m^{2}$

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At a point in a structure, there are two mutually perpendicular tensile stresses of 800 kg/cm2 and 400 kg/cm2. If the Poisson's ratio μ=0.25, what would be the equivalent stress in simple tension according to maximum principal strain theory?

The correct option is C 700 kg/cm2According to maximum principal strain theory fE=(σ1−μσ2)E The equivalent tensile stress f=800−0.25×400 =700kg/cm2

At a point in a structure, there are two mutually perpendicular tensile stresses of 800 $k g / c m^{2}$ and 400 $k g / c m^{2}$ . If the Poisson's ratio $μ = 0.25,$ what would be the equivalent stress in simple tension according to maximum principal strain theory?

The correct option is C 700 $k g / c m^{2}$
According to maximum principal strain theory
$\frac{f}{E} = \frac{(σ_{1} - μ σ_{2})}{E}$
The equivalent tensile stress
$f = 800 - 0.25 \times 400$

$= 700 k g / c m^{2}$