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Calculating Heights and Distances

At a point on...

Question

At a point on level ground,the angle of elevation of a vertical tower is found to be such that its tangent is 5/12.On walking 192m towards the tower,the tangent of the angle becomes 3/4.Find the height of the tower.

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Q. At a point on level ground, the angle of elevation of a vertical tower is found to be such that its tangent is

\frac{5}{12}

160

metres towards the tower, the tangent of the angle of elevation is

\frac{3}{4}

. The height of the tower is equal to

The angle of elevation $θ$ of a vertical tower from a point on the ground is such that its tangent is $(\frac{5}{12})$ . On walking 192 metres towards the tower in the same straight line, the tangent of the angle of elevation $Φ$ is found to be $(\frac{3}{4})$ . The height of the tower is :

Q. At a point, the angle of elevation of a tower is such that its tangent is

\frac{5}{12}

240 m

nearer the tower, the tangent of the angle of elevation becomes

\frac{3}{4}

. Find the height of the tower.

Q. At apoint on the ground yhe angle of elevations of a tower is such that its tangents is

\frac{4}{9}

60 m

towards the tower, the tangent of the angle of elevation changes to

\frac{2}{3}

. find the height of the tower.

Q. At a point A, the angle of elevation of a tower of a lower is such that its tangent is

\frac{5}{12};

on walking 120 meters nearer the tower the tangent of the angle of elevation is

\frac{3}{4} .

The height of the tower is :

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Calculating Heights and Distances

Standard X Mathematics

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