Question

At a selection, the probability of selection of A is $\frac{1}{7}$ and that of B is $\frac{1}{5}$. If A and B are independent events, then the probability that neither of them would be selected is

• A. $\frac{1}{35}$
• B. $\frac{2}{5}$
• C. $\frac{24}{35}$
• D. $\frac{12}{35}$

Answer 1

Answer: (C)

$\frac{24}{35}$

$P\left(A\right)=\frac{1}{7};P\left(B\right)=\frac{1}{5}$
Probability that neither of them would be selected is $=(1-P(A\left)\right)\times (1-P(B\left)\right)$
$=(1-\frac{1}{7})\times (1-\frac{1}{5})=\frac{24}{35}$