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Question

At a specific temperature, the energy densities for a black body for three different wavelengths are 10, 19 and 7 units. For these wavelengths if the absorption co-efficient of a body is respectively 0.8, 0.3 and 0.9 then the emissive power of this body for these wavelength are in the ratio:

A
10:19:7
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B
8:3:9
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C
8:5.7:6.3
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D
8:9.5:4.3
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Solution

The correct option is B 8:5.7:6.3
We know that Emissivepower=Energy density×absorption coefficient
So, E1:E2:E3=8:5.7:6.3

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