At a time, the image of sun formed due to reflection at air-water interface, is found to be highly polarized. If refractive index of water is μ=43, then the angle of the sun above the horizon is ?
A
37o
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B
53o
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C
30o
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D
60o
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Solution
The correct option is A37o Given,
μ=43
Let angle of incident is θi
From Bruster's law
μ=tanθi
μ=tanθiθi=tan−1μ
θi=tan−143=53.13
Here, θi is angle of sun from normal .
Angle of sun from Horizon is 90−θi=90−53.13=36.9≈37∘