At an election involving two candidates, $68$ votes were declared invalid. The winning candidate secures $52 %$ and wins by $98$ votes. The total number of votes polled are :

2382

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2450

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2518

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Solution

The correct option is C $2518$
Let total number of votes polled be x
Number of invalid votes= $68$
Number of valid votes= $x - 68$
then according to question
$(52 - 48) % o f (x - 68) = 98$
$4 % o f (x - 68) = 98$
$\frac{4}{100} + (x - 68) = 98$
$x - 68 = 98 + 25$
$x = 2450 + 68$
$x = 2518$
Therefore total votes polled= $2518$

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At an election involving two candidates, 68 votes were declared invalid. The winning candidate secures 52% and wins by 98 votes. The total number of votes polled are :

The correct option is C 2518Let total number of votes polled be xNumber of invalid votes=68Number of valid votes=x−68then according to question(52−48)%of(x−68)=984%of(x−68)=984100+(x−68)=98x−68=98+25x=2450+68x=2518Therefore total votes polled=2518

At an election involving two candidates, $68$ votes were declared invalid. The winning candidate secures $52 %$ and wins by $98$ votes. The total number of votes polled are :