Question

At an intersection the weaving ratio for N - E, E - S, S - W, and W - N direction are 0.70, 0.75, 0.71 and 0.69 respectively. The width of weaving section is 11.5 m, the length of weaving section is 46 m and average entry width is 8 m. The practical capacity (in PCU/hr) will be .

• A. 3276

Answer 1

The correct option is A 3276
Highest proportion of wearing traffic, p = 0.75

l = 46m, w = 11.5m, e = 8 m

Partical capacity, $Q=\frac{280w(1+\frac{e}{w})(1-\frac{p}{3})}{1+\frac{w}{l}}$

$=\frac{280\times 11.5(1+\frac{8}{11.5})(1-\frac{0.75}{3})}{1+\frac{11.5}{46}}=3276PCU/hr$